"함수 epochdate2date()"의 두 판 사이의 차이

(새 문서: 분류: date ;함수 epochdate2date() ==Bash== 분류: Bash <source lang='bash'> date -d "1970-01-01 + 0 day" +%Y-%m-%d # 1970-01-01 date -d "1970-01-01 + 11323 day" +%Y-%m-%...)
 
5번째 줄: 5번째 줄:
[[분류: Bash]]
[[분류: Bash]]
<source lang='bash'>
<source lang='bash'>
date -d "1970-01-01 + 0 day" +%Y-%m-%d
date +%Y-%m-%d -d "1970-01-01 + 0 day"
# 1970-01-01
# 1970-01-01
date -d "1970-01-01 + 11323 day" +%Y-%m-%d
date +%Y-%m-%d -d "1970-01-01 + 11323 day"
# 2001-01-01
# 2001-01-01
date -d "1970-01-01 + 20000 day" +%Y-%m-%d
date +%Y-%m-%d -d "1970-01-01 + 20000 day"
# 2024-10-04
</source>
<source lang='bash'>
date +%Y-%m-%d -d @$((86400*0))
# 1970-01-01
date +%Y-%m-%d -d @$((86400*11323))
# 2001-01-01
date +%Y-%m-%d -d @$((86400*20000))
# 2024-10-04
# 2024-10-04
</source>
</source>

2016년 7월 19일 (화) 17:21 판

함수 epochdate2date()

1 Bash

date +%Y-%m-%d -d "1970-01-01 + 0 day"
# 1970-01-01
date +%Y-%m-%d -d "1970-01-01 + 11323 day"
# 2001-01-01
date +%Y-%m-%d -d "1970-01-01 + 20000 day"
# 2024-10-04
date +%Y-%m-%d -d @$((86400*0))
# 1970-01-01
date +%Y-%m-%d -d @$((86400*11323))
# 2001-01-01
date +%Y-%m-%d -d @$((86400*20000))
# 2024-10-04

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