"파이썬 평균 구하기"의 두 판 사이의 차이

1번째 줄: 1번째 줄:
==개요==
==개요==
;파이썬 average()
;파이썬 average()
 
{{소스헤더|Python 3}}
<source lang='python'>
<source lang='python'>
nums = [1, 2, 3, 4]
nums = [1, 2, 3, 4]
print( sum(nums)/len(nums) )
print( sum(nums)/len(nums) )
# 2.5
# 2.5
nums = [1, 2, 3, 4, 5]
print( sum(nums)/len(nums) )
# 3.0
</source>


{{소스헤더|Python 2}}
<source lang='python'>
nums = [1, 2, 3, 4]
print( sum(nums)/len(nums) )
# 2
nums = [1, 2, 3, 4, 5]
nums = [1, 2, 3, 4, 5]
print( sum(nums)/len(nums) )
print( sum(nums)/len(nums) )
# 3
nums = [1, 2, 3, 4]
print( 1.0*sum(nums)/len(nums) )
# 2.5
nums = [1, 2, 3, 4, 5]
print( 1.0*sum(nums)/len(nums) )
# 3.0
# 3.0
</source>
</source>

2018년 8월 26일 (일) 21:57 판

1 개요

파이썬 average()
Python 3
nums = [1, 2, 3, 4]
print( sum(nums)/len(nums) )
# 2.5
nums = [1, 2, 3, 4, 5]
print( sum(nums)/len(nums) )
# 3.0
Python 2
nums = [1, 2, 3, 4]
print( sum(nums)/len(nums) )
# 2
nums = [1, 2, 3, 4, 5]
print( sum(nums)/len(nums) )
# 3

nums = [1, 2, 3, 4]
print( 1.0*sum(nums)/len(nums) )
# 2.5
nums = [1, 2, 3, 4, 5]
print( 1.0*sum(nums)/len(nums) )
# 3.0
NumPy
import numpy as np
a = np.array([1,2,3,4])
print( a.mean() )
# 2.5

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