5+8=?

1 개요

Solve this... 97% will fail this test.

• 1 + 4 = 5
• 2 + 5 = 12
• 3 + 6 = 21
• 5 + 8 = ?

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구분	행번호	이전값	진법
32	O	O
34		O
37	O
44	O
45
111	O		O
1101			O

2 32 (행번호, 이전값)

a ⊕ b = ( 행번호 × 2 ) + 3 + 이전값

• 1 ⊕ 4 = ( 1 × 2 ) + 3 + 0 = 5
• 2 ⊕ 5 = ( 2 × 2 ) + 3 + 5 = 12
• 3 ⊕ 6 = ( 3 × 2 ) + 3 + 12 = 21
• 5 ⊕ 8 = ( 4 × 2 ) + 3 + 21 = 32

3 34 (이전값)

a ⊕ b = ( a + b ) + 이전값

• 1 ⊕ 4 = ( 1 + 4 ) + 0 = 5
• 2 ⊕ 5 = ( 2 + 5 ) + 5 = 12
• 3 ⊕ 6 = ( 3 + 6 ) + 12 = 21
• 5 ⊕ 8 = ( 5 + 8 ) + 21 = 34

4 37 (행번호)

a ⊕ b = a + ( b × 행번호 )

• 1 ⊕ 4 = 1 + ( 4 × 1 ) = 5
• 2 ⊕ 5 = 2 + ( 5 × 2 ) = 12
• 3 ⊕ 6 = 3 + ( 6 × 3 ) = 21
• 5 ⊕ 8 = 5 + ( 8 × 4 ) = 37

5 44 (행번호)

a ⊕ b = ( a × b ) + 행번호

• 1 ⊕ 4 = ( 1 × 4 ) + 1 = 5
• 2 ⊕ 5 = ( 2 × 5 ) + 2 = 12
• 3 ⊕ 6 = ( 3 × 6 ) + 3 = 21
• 5 ⊕ 8 = ( 5 × 8 ) + 4 = 44

6 45

a ⊕ b = a + ( a × b )

• 1 ⊕ 4 = 1 + ( 1 × 4 ) = 5
• 2 ⊕ 5 = 2 + ( 2 × 5 ) = 12
• 3 ⊕ 6 = 3 + ( 3 × 6 ) = 21
• 5 ⊕ 8 = 5 + ( 5 × 8 ) = 45

7 111 (진법, 행번호)

a ⊕ b = ( a + b )(7-행번호)

• 1 ⊕ 4 = 1 + 4 = 5₍₁₀₎ = 5₍₆₎
• 2 ⊕ 5 = 2 + 5 = 7₍₁₀₎ = 12₍₅₎
• 3 ⊕ 6 = 3 + 6 = 9₍₁₀₎ = 21₍₄₎
• 5 ⊕ 8 = 5 + 8 = 13₍₁₀₎ = 111₍₃₎

8 1101 (진법)

a ⊕ b = ( a + b )(7-a)

• 1 ⊕ 4 = 1 + 4 = 5₍₁₀₎ = 5₍₆₎
• 2 ⊕ 5 = 2 + 5 = 7₍₁₀₎ = 12₍₅₎
• 3 ⊕ 6 = 3 + 6 = 9₍₁₀₎ = 21₍₄₎
• 5 ⊕ 8 = 5 + 8 = 13₍₁₀₎ = 1101₍₂₎

9 같이 보기

• 6/2(1+2)=?, 48/2(9+3)=?

10 참고

• https://www.quora.com/If-1+4-5-2+5-12-and-3+6-21-then-what-is-the-value-of-5+8