SWEA 1948 날짜 계산기

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SWEA 1948 날짜 계산기

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#	문제	풀이

2 C++

#include <iostream>
using namespace std;
int main() {
    int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    int T;
    scanf("%d", &T);
    int m1, d1, m2, d2;
    for(int tc=1; tc<=T; tc++) {
        scanf("%d %d %d %d", &m1, &d1, &m2, &d2);
        int diff = d2-d1+1;
        for( int i=m1; i<m2; i++) diff += days[i-1];
        printf("#%d %d\n", tc, diff);
    }
}

3 Java

import java.util.Scanner;
class Solution {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        int T = sc.nextInt();
        int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
        for(int t=1; t<=T; t++) {
            int m1 = sc.nextInt();
            int d1 = sc.nextInt();
            int m2 = sc.nextInt();
            int d2 = sc.nextInt();
            int dif = 1+d2-d1;
            for( int i=m1; i<m2; i++) dif += days[i-1];
            System.out.format("#%d %d\n", t, dif );   
        }
    }
}