"HR-SQL Average Population of Each Continent"의 두 판 사이의 차이

2018년 8월 16일 (목) 18:08 판

1 개요

HR-SQL Average Population of Each Continent

https://www.hackerrank.com/challenges/average-population-of-each-continent/problem

해커랭크 SQL
문제	DB2	MS SQL	MySQL	Oracle
HR-SQL Basic Join e
HR-SQL Asian Population
HR-SQL African Cities
HR-SQL Average Population of Each Continent
HR-SQL The Report
HR-SQL Top Competitors
HR-SQL Ollivander's Inventory
HR-SQL Challenges
HR-SQL Contest Leaderboard

2 MySQL

SELECT CO.CONTINENT, FLOOR(AVG(CI.POPULATION))
FROM CITY AS CI, COUNTRY AS CO
WHERE CO.CODE = CI.COUNTRYCODE
GROUP BY CO.CONTINENT;
# Africa 274439 
# Asia 693038 
# Europe 175138 
# Oceania 109189 
# South America 147435

@@ 1번째 줄: / 1번째 줄: @@
 ==개요==
 ;HR-SQL Average Population of Each Continent
-*
+* https://www.hackerrank.com/challenges/average-population-of-each-continent/problem
 {{HR-SQL 헤더}}
@@ 7번째 줄: / 7번째 줄: @@
 |}
-<source lang='sql'>
+==MySQL==
+<source lang='mysql'>
+SELECT CO.CONTINENT, FLOOR(AVG(CI.POPULATION))
+FROM CITY AS CI, COUNTRY AS CO
+WHERE CO.CODE = CI.COUNTRYCODE
+GROUP BY CO.CONTINENT;
+# Africa 274439
+# Asia 693038
+# Europe 175138
+# Oceania 109189
+# South America 147435
 </source>