"HR-SQL New Companies"의 두 판 사이의 차이

2021년 7월 31일 (토) 10:49 기준 최신판

1 개요[ | ]

HR-SQL New Companies

해커랭크 SQL
문제	DB2	MS SQL	MySQL	Oracle
HR-SQL Advanced Select e
HR-SQL Type of Triangle
HR-SQL The PADS
HR-SQL Occupations
HR-SQL Binary Tree Nodes
HR-SQL New Companies

2 DB2[ | ]

3 MS SQL[ | ]

4 MySQL[ | ]

SELECT company_code, founder,
(SELECT COUNT(DISTINCT lead_manager_code) FROM Lead_Manager WHERE company_code=C.company_code),
(SELECT COUNT(DISTINCT senior_manager_code) FROM Senior_Manager WHERE company_code=C.company_code),
(SELECT COUNT(DISTINCT manager_code) FROM Manager WHERE company_code=C.company_code),
(SELECT COUNT(DISTINCT employee_code) FROM Employee WHERE company_code=C.company_code)
FROM Company C
ORDER BY company_code;

5 Oracle[ | ]

@@ 8번째 줄: / 8번째 줄: @@
 ==DB2==
-<source lang='sql'>
+<syntaxhighlight lang='sql'>
-</source>
+</syntaxhighlight>
 ==MS SQL==
-<source lang='sql'>
+<syntaxhighlight lang='sql'>
-</source>
+</syntaxhighlight>
 ==MySQL==
-<source lang='mysql'>
+<syntaxhighlight lang='mysql'>
-</source>
+SELECT company_code, founder,
+(SELECT COUNT(DISTINCT lead_manager_code) FROM Lead_Manager WHERE company_code=C.company_code),
+(SELECT COUNT(DISTINCT senior_manager_code) FROM Senior_Manager WHERE company_code=C.company_code),
+(SELECT COUNT(DISTINCT manager_code) FROM Manager WHERE company_code=C.company_code),
+(SELECT COUNT(DISTINCT employee_code) FROM Employee WHERE company_code=C.company_code)
+FROM Company C
+ORDER BY company_code;
+</syntaxhighlight>
 ==Oracle==
-<source lang='sql'>
+<syntaxhighlight lang='sql'>
-</source>
+</syntaxhighlight>